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Problem #959
Cm=quy nap \(1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n-1}<n\)
| Status: | Closed | Start Date: | 30-12-2011 | |
|---|---|---|---|---|
| Priority: | Normal | Due date: | ||
| Assigned to: |  tanphu |
% Done: | 0% |
|
| Category: | Quy nạp | |||
| Target version: | - | |||
| Votes: | 0/0 |
Description
Cm=quy nap: \(1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n-1}<n\)
mọi người giúp em... mai em thi rồi!
History
Updated by tanphu 5 months ago
- Subject changed from Cm=quy nap: 1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n-1}<n to Cm=quy nap \(1+ \dfrac{1}{2}+\dfrac{1}{3}+...+\dfrac{1}{2^n-1}<n\)
- Category set to Quy nạp
- Status changed from New to Assigned
- Assigned to set to tanphu
